Now there is one puzzle pops up at B) (2)
B)..PP B P, bet B to break 2S of PP to form
(2) if lost get ..PP B P
P then follow the run keep betting P until a lose;
What if the next bet P is lost? It seems at B)(2) it's a 1-2 then we bet P to prevent the 1-2-3, if lose we get ..PP B P P
B. It's a premature of 1-2-3. From here we should lead it to E).
Look not too difficult to play on hand but not easy to code in program...
lol
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Here is the rule description:
Here are the rules--
Bet against a pattern of 1-2-3. Example: B-PP-BBB or P-BB-PPP.
Whatever the first hand is (B or P), you follow the same side to
prevent a single 1. If you win the bet, follow the side for as long as it
goes. If you lost the 1st bet, now you have 1-1 and would bet against
the hand that won to prevent 1-2. If you lost that bet, you would
follow the side of the 2 for as long as it goes. If you won against the 1-
1, you still have 1-1 and you continue to bet opposite to keep the 2nd
1 from becoming a 2. Continue betting for the zig-zag, for as long as it
continues. It will always end as 1-2 and you will follow the 2 for as
long as it goes. If the 1-2 becomes 1-2-1, you bet opposite to prevent 1-
2-3. If you win the 1st or 2nd bet to prevent the 3, from happening,
follow that side for as long as it goes. If you lose all 3 bets to prevent
the 3, follow the 3 for as long as it goes.
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